C = \(\left(\dfrac{x}{x+2}+\dfrac{4x+4}{x^2+2x}\right):\dfrac{x+2}{x}\)
D = \(\left(\dfrac{3x^2+4}{x^2+2x}-\dfrac{2x-4}{x+2}\right).\dfrac{2x}{x^2-4}\)
E = \(\dfrac{x+1}{x}:\left(\dfrac{x-1}{x-3}-\dfrac{4x-6}{x^2-3x}\right)\)
G = \(\dfrac{x^2-6x+9}{x}.\left(\dfrac{2x^2-4x+6}{x^2-2x}-\dfrac{x+1}{x-2}\right)\)
giải chi tiết giúp mình nhaa:33
a: \(C=\dfrac{x^2+4x+4}{x\left(x+2\right)}\cdot\dfrac{x}{x+2}=\dfrac{\left(x+2\right)^2}{\left(x+2\right)^2}=1\)
b: \(D=\dfrac{3x^2+4-2x^2+4x}{x\left(x+2\right)}\cdot\dfrac{2x}{\left(x-2\right)\left(x+2\right)}\)
\(=\dfrac{\left(x+2\right)^2}{\left(x+2\right)}\cdot\dfrac{2}{\left(x-2\right)\left(x+2\right)}=\dfrac{2}{x-2}\)
c: \(E=\dfrac{x+1}{x}:\dfrac{x^2-x-4x+6}{x\left(x-3\right)}\)
\(=\dfrac{x+1}{x}\cdot\dfrac{x\left(x-3\right)}{\left(x-3\right)\left(x-2\right)}=\dfrac{x+1}{x-2}\)
