B=\(\frac{5}{9}\)x{\(\frac{7}{13}\)+\(\frac{9}{13}\)-\(\frac{3}{13}\)}
B=\(\frac{5}{9}\)x 1
B=\(\frac{5}{9}\)
Vậy B=\(\frac{5}{9}\)
Chúc bạn hok tốt
B = \(\frac{5}{9}.\frac{7}{13}+\frac{5}{9}.\frac{9}{13}-\frac{5}{9}.\frac{3}{13}\)
Ta thấy có phân số \(\frac{5}{9}\) là thừa số chung
\(\Leftrightarrow\frac{5}{9}\left(\frac{7}{13}+\frac{9}{13}-\frac{3}{13}\right)=\frac{5}{9}\left(\frac{7+9+3}{13}\right)\)
\(=\frac{5}{9}.\frac{19}{13}\left(\frac{5.19}{9.13}\right)\)
\(=\frac{95}{117}\)
Làm lại
\(B=\frac{5}{9}.\frac{7}{13}+\frac{5}{9}.\frac{9}{13}-\frac{5}{9}.\frac{3}{13}\)
Ta thấy phân số \(\frac{5}{9}\) là thừa số chung . Ta có :
\(\Leftrightarrow\frac{5}{9}\left(\frac{7}{13}+\frac{9}{13}-\frac{3}{13}\right)\)
\(=\frac{5}{9}.\frac{13}{13}=\frac{5}{9}.1\)
\(=\frac{5}{9}\)
\(=\frac{5}{9}x\cdot\left(\frac{7}{13}+\frac{9}{13}-\frac{3}{13}\right)=\frac{5}{9}x\cdot\left(\frac{16}{13}-\frac{3}{13}\right)=\frac{5}{9}x\cdot\frac{13}{13}=\frac{5}{9}x\cdot1=\frac{5}{9}x\)