\(B=\dfrac{1}{6\cdot10}+\dfrac{1}{10\cdot14}+...+\dfrac{1}{402\cdot406}\)
\(=\dfrac{1}{4}\left(\dfrac{1}{6}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{14}+...+\dfrac{1}{402}-\dfrac{1}{406}\right)\)
\(=\dfrac{1}{4}\cdot\dfrac{400}{2436}=\dfrac{100}{2436}=\dfrac{25}{609}\)