a) x(x + 1) - 2x(x - 2) = x2 + x - 2x2 + 4x = -x2 + 5x
b) -3x(x - 1) + (x - 1)(x + 1) = -3x2 + 3x + x2 - 1 = -2x2 + 3x - 1
c) (3x - 2)(3x + 2) - (x - 1)(x + 2) = 9x2 - 4 - x2 - x + 2
= 8x2 - x - 2
a, x(x+1) - 2x(x -2 )
= x2 +x - 2x2 + 4x = -x2 + 5x
b, -3x( x - 1 ) + ( x -1 ) ( x+1 )
= -3x2 + 3x + x2 -1
= -2x2 + 3x -1
c, ( 3x-2 ) ( 3x + 2 ) - ( x -1 ) ( x +2 )
= 9x2 - 4 - ( x2 + 2x -x -2 )
= 9x2 -4 - x2 -2x + x + 2
= 8x2 -x -2
*Sxl
Trả lời:
a) x ( x + 1 ) - 2x ( x - 2 ) = x2 + x - 2x2 + 4x = - x2 + 5x
b) - 3x ( x - 1 ) + ( x - 1 ) ( x + 1 ) = - 3x2 + 3x + x2 - 1 = - 2x2 + 3x - 1
c) ( 3x - 2 ) ( 3x + 2 ) - ( x - 1 ) ( x + 2 ) = 9x2 - 4 - ( x2 + 2x - x - 2 ) = 9x2 - 4 - x2 - 2x + x + 2 = 8x2 - x - 2