Question

Bài 1 thục hiện phép tính

a) 2x[(195+35:7):8:+195]-400=

b)4x{3mũ 2x[(5mũ 2+2mũ3):11mũ 1 ]-26}+2000

Answer 1

a, = 390

b, = 2004

Answer 2

a) 390

b) 2004

Answer 3

a) \(2\cdot\left[\left(195+35:7\right):8+195\right]-400\)

\(=2\cdot\left[\left(195+5\right):8+195\right]-400\)

 \(=2\cdot\left(200:8+195\right)-400\)

\(=2\cdot220-400\)

\(=440-400=40\)

b) \(4\cdot\left\{3^2\cdot\left[\left(5^2+2^3\right):11^1\right]-26\right\}+2000\)

\(=4\cdot\left[3^2\cdot\left(33:11\right)-26\right]+2000\)

\(=4\cdot\left(3^2\cdot3-26\right)+2000\)

\(=4\cdot1+2000=4+2000+2004\)

Answer 4

\(a,\text{ }2\cdot\left(\left\{195+35\text{ : }7\right\}\text{ : }8+195\right)-400\)

\(=2\cdot\left(\left\{195+5\right\}\text{ : }8+195\right)-400\)

\(=2\cdot\left(200\text{ : }8+195\right)-400\)

\(=2\cdot\left(25+195\right)-400\)

\(=2\cdot220-400\)

\(=440-400\)

\(=40\)