a: Sửa đề: \(\dfrac{2x+1}{2x^2-2}\)
\(\dfrac{2x+1}{2x^2-2}=\dfrac{2x+1}{2\left(x-1\right)\left(x+1\right)}\)
\(\dfrac{1}{x-1}=\dfrac{2\left(x+1\right)}{2\left(x-1\right)\left(x+1\right)}=\dfrac{2x+2}{2\left(x-1\right)\left(x+1\right)}\)
b: \(\dfrac{3x+2}{x^2-2}=\dfrac{\left(3x+2\right)\left(2x+1\right)}{\left(x^2-2\right)\left(2x+1\right)}=\dfrac{6x^2+7x+2}{\left(x^2-2\right)\left(2x+1\right)}\)
\(\dfrac{x+1}{2x+1}=\dfrac{\left(x+1\right)\left(x^2-2\right)}{\left(2x+1\right)\left(x^2-2\right)}=\dfrac{x^3-2x+x^2-2}{\left(2x+1\right)\left(x^2-2\right)}\)
c: \(\dfrac{3}{x-1}=\dfrac{3x-6}{\left(x-1\right)\left(x-2\right)}\)
\(\dfrac{4}{x-2}=\dfrac{4x-4}{\left(x-2\right)\left(x-1\right)}\)
