Question

a,x^2-x+1/4=0        b,5x^2-5=4(x^2-2x+1)
c,(2x+1)^2=(x-3)^2

Answer 1

`a, x^2-x+1/4=0`

`<=>(x-1/2)^2=0`

`<=>x-1/2=0`

`<=>x=1/2`

 

 

`b,5x^2-5=4(x^2-2x+1)`

`<=>5(x-1)(x+1)-4(x-1)^2=0`

`<=>(x-1)(5x+5-4x+4)=0`

`<=>(x-1)(x+9)=0`

`<=>x=-9` hoặc `x=1`

 

 

`c,(2x+1)^2=(x-3)^2`

`<=>(2x+1-x+3)(2x+1+x-3)=0`

`<=>(x+4)(3x-2)=0`

`<=>x=2/3` hoặc `x=-4`

Answer 2

a: =>(x-1/2)^2=0

=>x-1/2=0

=>x=1/2

b:=>5(x-1)(x+1)-4(x-1)^2=0

=>(x-1)(5x+5-4x+4)=0

=>(x-1)(x+9)=0

=>x=-9 hoặc x=1

c: =>(2x+1-x+3)(2x+1+x-3)=0

=>(x+4)(3x-2)=0

=>x=2/3 hoặc x=-4