\(a,x-\frac{x+1}{3}=\frac{2x+1}{5}\)
\(\Leftrightarrow\frac{15x}{15}-\frac{5\left(x+1\right)}{15}=\frac{3\left(2x+1\right)}{15}\)
\(\Leftrightarrow15x-5x-5=6x+3\)
\(\Leftrightarrow15x-5x-6x=3+5\)
\(\Leftrightarrow4x=8\)
\(\Leftrightarrow x=2\)
Vậy pt có No là x = 2
b,\(\frac{2x-1}{3}-\frac{5x+2}{7}=x+13\)
\(\Leftrightarrow\frac{7\left(2x-1\right)}{21}-\frac{3\left(5x+2\right)}{21}=\frac{21\left(x+3\right)}{21}\)
\(\Leftrightarrow14x-7-15x-6=21x+273\)
\(\Leftrightarrow14x-5x-21x=273+7+6\)
\(\Leftrightarrow-22x=286\)
\(\Leftrightarrow x=-13\)
Vậy pt có No là x= -13
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