a: \(Q=\dfrac{\left(x+1\right)^2+x\left(x-1\right)-x}{\left(x-1\right)\left(x+1\right)}:\dfrac{\left(x+1\right)^2-\left(x-1\right)^2}{\left(x-1\right)\left(x+1\right)}\)
\(=\dfrac{x^2+2x+1+x^2-x-x}{\left(x-1\right)\left(x+1\right)}\cdot\dfrac{\left(x-1\right)\left(x+1\right)}{x^2+2x+1-x^2+2x-1}\)
\(=\dfrac{2x^2+1}{4x}\)
b: |x-3|=2
=>x-3=2 hoặc x-3=-2
=>x=5(nhận) hoặc x=1(loại)
Khi x=5 thì \(G=\dfrac{2\cdot5^2+1}{4\cdot5}=\dfrac{51}{20}\)
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