Question

\(A=\frac{\left(0,4-\frac{2}{\sqrt{81}}+\frac{2}{11}\right)}{\left(1,4-\frac{7}{\sqrt{81}}+\frac{7}{11}\right)}\)

Answer 1

\(A=\frac{2}{7}\)

Answer 2

\(A=\frac{\left(0,4-\frac{2}{\sqrt{81}}+\frac{2}{11}\right)}{1,4-\frac{7}{\sqrt{81}}+\frac{7}{11}}=\frac{2\left(0,2-\frac{1}{\sqrt{81}}+\frac{1}{11}\right)}{7\left(0,2-\frac{1}{\sqrt{81}}+\frac{1}{11}\right)}=\frac{2}{7}\)

Answer 3

Ta có: A=\(\frac{\left(0,4-\frac{2}{\sqrt{81}}+\frac{2}{11}\right)}{\left(1,4-\frac{7}{\sqrt{81}}+\frac{7}{11}\right)}\)

            =\(\frac{\frac{2}{5}-\frac{2}{9}+\frac{2}{11}}{\frac{7}{5}-\frac{7}{9}+\frac{7}{11}}\)

            =\(\frac{2.\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}{7.\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}\)

       => A=\(\frac{2}{7}\)