Question

a)\(\dfrac{3}{35}\)-\((\)\(\dfrac{3}{5}\)+x\()\)=\(\dfrac{2}{7}\)

Answer 1

\(\dfrac{3}{35}-\left(\dfrac{3}{5}+x\right)=\dfrac{2}{7}\)

\(\left(\dfrac{3}{5}+x\right)=\dfrac{3}{35}-\dfrac{2}{7}\)

\(\dfrac{3}{5}+x=\dfrac{-1}{5}\)

\(x=\dfrac{-1}{5}-\dfrac{3}{5}\)

\(x=\dfrac{-4}{5}\)

Answer 2

Ta có : $\dfrac{3}{35}-(\dfrac{3}{5}+x)=\dfrac{2}{7}$

$=>(\dfrac{3}{5}+x)=\dfrac{3}{35}-\dfrac{2}{7}$

$=>\dfrac{3}{5}+x=\dfrac{-7}{35}=\dfrac{-1}{5}$

$=>x=\dfrac{-1}{5}-\dfrac{3}{5}$

$=>x=\dfrac{-4}{5}$

Answer 3

Ta có:

\(\dfrac{3}{35}-\left(\dfrac{3}{5}+x\right)=\dfrac{2}{7}\)

=>\(\dfrac{3}{5}+x=\dfrac{3}{35}-\dfrac{2}{7}\)

=>\(\dfrac{3}{5}+x=-\dfrac{1}{5}\)

=>\(x=-\dfrac{1}{5}-\dfrac{3}{5}\)

=>\(x=-\dfrac{4}{5}\)