Question

a,(9x+1)-(4x+2)

b, (3x^2x+1)-( 3x^2 -4x+5)

Answer 1

Đề bài là gì bạn , chẳng nhẽ tính ?

a) (9x + 1) - (4x + 2) = 9x + 1 - 4x - 2 = (9x - 4x) + (1 - 2) = 5x - 1

b) (3x³ + 1) - (3x² - 4x + 5) = 3x³ + 1 - 3x² + 4x - 5 = 3x³ - 3x² + 4x + (1 - 5) = 3x³ - 3x² + 4x  - 4

Answer 2

a) \(\left(9x+1\right)-\left(4x+2\right)\)

\(=9x+1-4x-2\)

\(=5x-1\)

b) \(\left(3x^2+1\right)-\left(3x^2-4x+5\right)\)

\(=3x^2+1-3x^2+4x-5\)

\(=4x-4\)

Answer 3

a) (9x+1) - (4x+2)

\(9x+1-4x-2\)

\(\Leftrightarrow5x-1\)

Answer 4

( 9x + 1 ) - ( 4x + 2 )

= 9x + 1 - 4x - 2

= 5x - 1

( 3x² + 1 ) - ( 3x² - 4x + 5 )

= 3x² + 1 - 3x² + 4x - 5

= 4x - 4 = 4( x - 1 )

Answer 5

a, \(\left(9x+1\right)-\left(4x+2\right)=9x+1-4x-2=5x-1\)

b, \(\left(3x^2+1\right)-\left(3x^2-4x+5\right)=3x^2+1-3x^2+4x-5=4x-4\)

Answer 6

a,(9x+1)-(4x+2)

=9x+1-4x-2

= ( 9x - 4x ) - ( 1 - 2)

= 5x - 1

b, (3x²+1)-( 3x² -4x+5)

= 3x²+1 - 3x² +4x - 5

= ( 3x² - 3x²) + ( 1 - 5) + 4x

= -4 + 4x