Question

A = \(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)

Giải đầy đủ ra mới tk nhé

Answer 1

\(A=\frac{11.3^{22+7}-\left(3^2\right)^{15}}{2^2.\left(3^{14}\right)^2}=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}=\frac{3^{29}.\left(11-3\right)}{2^2.3^{28}}=\frac{3^{29}.2^3}{2^2.3^{28}}=\hept{\frac{3}{ }}\)\(=3.2=6\)

Answer 2

bạn bỏ phần \(=\hept{\begin{cases}3\\\end{cases}}\)mình ghi lộn