Question

A= (9 - 3/5 +2/3) - (7+ 7/5 - 3/2) - (3 - 9/5 + 5/2)tính theo 2 cách

Answer 1

TH1: \(A=\left(9-\frac35+\frac23\right)-\left(7+\frac75-\frac32\right)-\left(3-\frac95+\frac52\right)\)

\(=\left(\frac{135}{15}-\frac{9}{15}+\frac{10}{15}\right)-\left(\frac{70}{10}+\frac{14}{10}-\frac{15}{10}\right)-\left(\frac{30}{10}-\frac{18}{10}+\frac{25}{10}\right)\)

\(=\frac{136}{15}-\frac{69}{10}-\frac{37}{10}=\frac{136}{15}-\frac{106}{10}=\frac{272}{30}-\frac{318}{30}=-\frac{46}{30}=-\frac{23}{15}\)

TH2: \(A=\left(9-\frac35+\frac23\right)-\left(7+\frac75-\frac32\right)-\left(3-\frac95+\frac52\right)\)

\(=9-\frac35+\frac23-7-\frac75+\frac32-3+\frac95-\frac52\)

\(=\left(9-7-3\right)+\left(-\frac35-\frac75+\frac95\right)+\left(\frac32-\frac52\right)+\frac23=-1-\frac15-1+\frac23\)

\(=-2-\frac15+\frac23=-\frac{30}{15}-\frac{3}{15}+\frac{10}{15}=-\frac{23}{15}\)