a) Ta có:
\(\dfrac{2}{3}=\dfrac{2\times8}{3\times8}=\dfrac{16}{24}\)
\(\dfrac{5}{8}=\dfrac{5\times3}{8\times3}=\dfrac{15}{24}\)
Vì \(16>15\) nên \(\dfrac{16}{24}>\dfrac{15}{24}\)
Vậy \(\dfrac{2}{3}>\dfrac{5}{8}\)
b) Ta có:
\(\dfrac{1}{4}=\dfrac{1\times3}{4\times3}=\dfrac{3}{12}\)
Vì \(3< 7\) nên \(\dfrac{3}{12}< \dfrac{7}{12}\)
Vậy \(\dfrac{1}{4}< \dfrac{7}{12}\)
c) Ta có:
\(\dfrac{5}{6}=\dfrac{5\times4}{6\times4}=\dfrac{20}{24}\)
\(\dfrac{3}{8}=\dfrac{3\times3}{8\times3}=\dfrac{9}{24}\)
Vì \(20>9\) nên \(\dfrac{20}{24}>\dfrac{9}{24}\)
Vậy \(\dfrac{5}{6}>\dfrac{3}{8}\)
#pero_
a , 2/3 > 5/8
b , 1/4 < 7/12
c , 5/6 > 3/8
