Question

A =2²⁰¹⁵ +1/2²⁰¹⁶+1 ; B= 2²⁰¹⁶+1/2²⁰¹⁷+1

SO SÁNH A VÀ B

 

Answer 1

a>b

chúc bạn vui vẻ cả năm

Answer 2

a>b

vì a lớn hơn b vì câu đầu tiên đó bạn để ý đi

Answer 3

Vì 2²⁰¹⁵ + 1 < 2²⁰¹⁶ + 1 

\(\Rightarrow A=\frac{2^{2015}+1}{2^{2016}+1}< \frac{2^{2015}+1+1}{2^{2016}+1+1}=\frac{2^{2015}+2}{2^{2016}+2}=\frac{2\left(2^{2014}+1\right)}{2\left(2^{2015}+1\right)}=\frac{2^{2014}+1}{2^{2015}+1}=B\)

\(\Rightarrow A< B\)

Answer 4

a>b. chọn mình nha

Answer 5

Nhầm , làm lại nha

Vì 2²⁰¹⁶ + 1 < 2²⁰¹⁷ + 1

\(\Rightarrow B=\frac{2^{2016}+1}{2^{2017}+1}< \frac{2^{2016}+1+1}{2^{2017}+1+1}=\frac{2^{2016}+2}{2^{2017}+2}=\frac{2\left(2^{2015}+1\right)}{2\left(2^{2016}+1\right)}=\frac{2^{2015}+1}{2^{2016}+1}=A\)

\(\Rightarrow A>B\)

Answer 6

Ta có: \(A=\frac{2^{2015}+1}{2^{2016}+1}\Rightarrow10A=\frac{2^{2016}+2}{2^{2016}+1}=1+\frac{1}{2^{2016}+1}\)

\(B=\frac{2^{2016}+1}{2^{2017}+1}\Rightarrow2B=\frac{2^{2017}+2}{2^{2017}+1}=1+\frac{1}{2^{2017}+1}\)

Vì \(\frac{1}{2^{2016}+1}>\frac{1}{2^{2017}+1}\Rightarrow1+\frac{1}{2^{2016}+1}>1+\frac{1}{2^{2017}+1}\Rightarrow A>B\)

Vậy A > B

Answer 7

Ta có : \(A=\frac{2^{2015}+1}{2^{2016}+1}\Rightarrow2A=\frac{2^{2016}+1+1}{2^{2016}+1}=1+\frac{1}{2^{2016}+1}\)

\(B=\frac{2^{2016}+1}{2^{2017}+1}\Rightarrow2B=\frac{2^{2017}+1+1}{2^{2017}+1}=1+\frac{1}{2^{2017}+1}\)

Vì \(\frac{1}{2^{2016}+1}>\frac{1}{2^{2017}+1}\Rightarrow1+\frac{1}{2^{2016}+1}>1+\frac{1}{2^{2017}+1}\Rightarrow2A>2B\Rightarrow A>B\)

Vậy A > B