a) \(\dfrac{17}{2}\cdot x-1=\dfrac{3}{4}\)
\(\Rightarrow\dfrac{17}{2}\cdot x=\dfrac{3}{4}+1\)
\(\Rightarrow\dfrac{17}{2}\cdot x=\dfrac{7}{4}\)
\(\Rightarrow x=\dfrac{7}{4}:\dfrac{17}{2}\)
\(\Rightarrow x=\dfrac{7}{34}\)
b) \(\dfrac{3}{7}=\dfrac{-24}{x}\)
\(\Rightarrow x=\dfrac{7\cdot-24}{3}\)
\(\Rightarrow x=7\cdot-8\)
\(\Rightarrow x=-56\)
c) \(\dfrac{7}{8}+x=\dfrac{3}{5}\)
\(\Rightarrow x=\dfrac{3}{5}-\dfrac{7}{8}\)
\(\Rightarrow x=-\dfrac{11}{40}\)
d) \(\dfrac{1}{3}:\left(2x-1\right)=\dfrac{-4}{24}\)
\(\Rightarrow\dfrac{1}{3}:\left(2x-1\right)=\dfrac{-1}{6}\)
\(\Rightarrow2x-1=\dfrac{1}{3}:\dfrac{-1}{6}\)
\(\Rightarrow2x-1=-2\)
\(\Rightarrow2x=-1\)
\(\Rightarrow x=-\dfrac{1}{2}\)
e) \(\left(3x+2\right)\cdot\left(-\dfrac{2}{5}x-7\right)=0\)
TH1: \(3x+2=0\)
\(\Rightarrow3x=-2\)
\(\Rightarrow x=-\dfrac{2}{3}\)
TH2: \(-\dfrac{2}{5}x-7=0\)
\(\Rightarrow-\dfrac{2}{5}x=7\)
\(\Rightarrow x=7:-\dfrac{2}{5}\)
\(\Rightarrow x=-\dfrac{35}{2}\)
