Question

(9x+1)-(96-33)=10

Tìm x

Answer 1

(9x+1)-(96-33)=10

=>9x+1-63=10

=>9x-62=10

=>9x=72

=>\(x=\dfrac{72}{9}=8\)

Answer 2

`(9x+1)-(96-33)=10`

`=> 9x + 1 - 63 = 10`

`=> 9x - 62 = 10`

`=> 9x = 10 + 62`

`=> 9x = 72`

`=> x = 72 : 9`

`=> x = 8`

Vậy `x = 8`