Tìm x
72x+72x+2=2450
Tìm x biết:
\(7^{2x}+7^{2x+2}=2450\)
\(7^{2x}+7^{2x+2}=2450\)
Tìm x
a,(2x+1).\(\left(x-\frac{1}{7}\right)=0\)
b,\(7^{2x}+7^{2x+2}=2450\)
a) 2x+2x+3=144
b) 72x+72x+2=2450
Tìm x, biết:
72x + 72x+2 = 2450
Tìm x:
a. \(\frac{x-2}{2}\)=\(\frac{-4}{\left(x-2\right)^2}\)
b. \(7^{2x}\)+ \(7^{2x+2}\)= 2450
\(7^{2x}+7^{2x+2}=2450\)
\(7^{2x}+7^{2x+2}=2450\)