Question

\(/5x-4/=/x+2/\)

\(/x-1/=3x+2\)

Giúp mk hai phép này zới

Answer 1

\(\left|x-1\right|=3x+2\)

Xét các trường hợp:

TH1:   x - 1 = 3x + 2

        x - 3x = 2 + 1

        -2x     = 3

           x     = \(\frac{-3}{2}\)

TH2:   1 - x = 3x + 2

       -x - 3x = 2 - 1

          -4x   = 1

             x   = \(\frac{-1}{4}\)

 Vậy x \(\in\left\{\frac{-3}{2};\frac{-1}{4}\right\}\)

Answer 2

\(\left|5x-4\right|=\left|x+2\right|\)

\(\Rightarrow\left|5x-4\right|-\left|x+2\right|=0\)

\(\Rightarrow\left(5x-4\right)-\left(x+2\right)=0\)

\(\Rightarrow5x-4-x-2=0\)

\(\Rightarrow4x-6=0\)

\(\Rightarrow4x=6\)

\(\Rightarrow x=\frac{3}{2}\)