\(\frac{5}{-x^2+5x-6}+\frac{x+3}{2-x}=0\left(x\ne2,x\ne3\right)\)
\(\frac{5}{\left(2-x\right)\left(x-3\right)}+\frac{x+3}{2-x}=0\)
\(\Leftrightarrow5-\left(x+3\right)\left(x-3\right)=0\Leftrightarrow5-x^2+9=0\)
\(\Leftrightarrow4-x^2=0\Leftrightarrow\left[{}\begin{matrix}x=-2\left(tm\right)\\x=2\left(ktm\right)\end{matrix}\right.\)
Kl;........
(P/s: lần sau bn nhớ chép đề đúng ạ!!>>)
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