Question

4x(3x^2-x)-(2x+3)(6x^2-3x+1)

Answer 1

4x(3x² - x) - (2x +3)(6x² - 3x +1)

= 12x³ - 4x² - (12x³ - 6x² +2x + 18x² - 9x +3)

= 12x³ - 4x² - 12x³ + 6x² - 2x - 18x² + 9x - 3

= -16x² +7x - 3

Answer 2

\(4x\left(3x^2-x\right)-\left(2x+3\right)\left(6x^2-3x+1\right)\\ =12x^3-4x^2-12x^3+6x^2-2x-18x^2+9x-3\\ =-16x^2+7x-3\)

Answer 3

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Answer 4

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