`(3x+2)-(x-1)=4(x+1)`
`=>3x+2-x+1=4x+4`
`=>2x+3=4x+4`
`=>4x-2x=3-4`
`=>2x=-1`
`=>x=-1/2`
\(3x+2-x+1=4x+4\\ 2x+3-4x-4=0\\ -2x-1=0\\ -2x=1\\ x=1:\left(-2\right)\\ x=-\dfrac{1}{2}\)
\(\left(3x+2\right)-\left(x-1\right)=4\left(x+1\right)\)
\(\Rightarrow3x+2-x+1=4x+4\)
\(\Rightarrow2x+3=4x+4\)
\(\Rightarrow4x-2x=3-4\)
\(\Rightarrow2x=-1\)
\(\Rightarrow x=-\dfrac{1}{2}\)
Vậy \(x=-\dfrac{1}{2}\)
\(#chuahe\)