Question

(3x + 2)² – (1 - 2x)² = 0(Tìm x)

Answer 1

\(\left(3x+2\right)^2-\left(2x-1\right)^2=0\)

\(\Leftrightarrow\left(3x+2-2x+1\right)\left(3x+2+2x-1\right)=0\)

\(\Leftrightarrow\left(x+3\right)\left(5x+1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=-\dfrac{1}{5}\end{matrix}\right.\)

Answer 2

\(\left(3x+2\right)^2-\left(1-2x\right)^2=0\)

\(\Rightarrow\left(3x+2-1+2x\right)\left(3x+2+1-2x\right)=0\)

\(\Rightarrow\left(5x+1\right)\left(x+3\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=-\dfrac{1}{5}\\x=-3\end{matrix}\right.\)