\(3x+14⋮x+2\)
=>\(3x+6+8⋮x+2\)
=>\(8⋮x+2\)
=>\(x+2\in\left\{1;-1;2;-2;4;-4;8;-8\right\}\)
=>\(x\in\left\{-1;-3;0;-4;2;-6;6;-10\right\}\)
3x + 14 = 3x + 6 + 8
= 3(x + 2) + 8
Để (3x + 14) ⋮ (x + 2) thì 8 ⋮ (x + 2)
⇒ x + 2 ∈ Ư(8) = {-8; -4; -2; -1; -1; 2; 4; 8}
⇒ x ∈ {-10; -6; -4; -3; -1; 0; 2; 6}