Question

3+2^x-1=24-[4²-(2²-1)]

Answer 1

\(3+2^{x-1}=24-\left[4^2-\left(2^2-1\right)\right]\)

\(\Leftrightarrow2^{x-1}=24-16+3-3\)

\(\Leftrightarrow x-1=3\)

hay x=4

Answer 2

\(3+2^{x-1}=24-\left[4^2-\left(2^2-1\right)\right]\)

<=> \(3+2^{x-1}=11\)

<=> \(2^{x-1}=8\)

<=> \(2^{x-1}=2^3\)

<=> x - 1 = 3

<=> x = 4

Answer 3

`3 + 2^(x-1)=24-[4^2-(2^2-1)]`

`=> 3+2^(x-1)=24-[16-(4-1)]`

`=>3+2^(x-1)=24-[16-3]`

`=> 3+2^(x-1)=24-13`

`=> 3+2^(x-1)=11`

`=> 2^(x-1)=11-3`

`=> 2^(x-1)=8`

`=> 2^(x-1)=2^3`

`=> x-1=3`

`=> x=3+1`

`=> x=4`

Vậy `x=4`