Question

(2x+3)(\(\frac{3x+8}{2-7x}\)+1)=(x-5)(\(\frac{3x+8}{2-7x}\)+1)

Answer 1

\(\left(2x+3\right)\left(\frac{3x+8}{2-7x}+1\right)=\left(x-5\right)\left(\frac{3x+8}{2-7x}+1\right)\) (ĐKXĐ: x \(\ne\) \(\frac{2}{7}\))

\(\Leftrightarrow\) \(\left(2x+3\right)\left(\frac{3x+8}{2-7x}+1\right)-\left(x-5\right)\left(\frac{3x+8}{2-7x}+1\right)=0\)

\(\Leftrightarrow\) \(\left(\frac{3x+8}{2-7x}+1\right)\left(2x+3-x+5\right)=0\)

\(\Leftrightarrow\) \(\left(\frac{10-4x}{2-7x}\right)\left(x+8\right)=0\)

\(\Leftrightarrow\) \(\frac{10-4x}{2-7x}=0\) hoặc x + 8 = 0

\(\Leftrightarrow\) x = \(\frac{5}{2}\) và x = -8

Vậy S = {\(\frac{5}{2}\); -8}

Chúc bn học tốt!!