|2x+2017|=2019
=>\(|^{2x+2017=2019}_{2x+2017=-2019}\)
=>\(|^{2x=2019-2017}_{2x=-2019-2017}\)
=>\(|^{2x=2}_{2x=-4036}\)
=>\(|^{x=2:2}_{x=-4036:2}\)
=>\(|^{x=1}_{x=-2018}\)
Vậy x\(\in\left\{1;-2018\right\}\)
Chúc bn học tốt!
|2x + 2017|= 2019
\(\Rightarrow\)2x + 2017 = 2019 & 2x + 2017 = -2019
TH1: 2x + 2017 = 2019
2x = 2019 - 2017
2x = 2
x = 2 ÷ 2
x = 1
TH2: 2x + 2017 = -2019
2x = -2019 - 2017
2x = - 4036
x = -4036 ÷ 2
x = - 2018
Vây x \(\in\){ 1 ; -2018}
