Question

2x = 3y ; 4y = 5z vafà x+y+1=1

Answer 1

\(2x=3y\Rightarrow\dfrac{x}{\dfrac{3}{2}}=\dfrac{y}{1}\) (1)

\(4y=5z\Rightarrow\dfrac{y}{1}=\dfrac{z}{\dfrac{4}{5}}\) (2)

\(\left(1\right);\left(2\right)\Rightarrow\dfrac{x}{\dfrac{3}{2}}=\dfrac{y}{1}=\dfrac{z}{\dfrac{4}{5}}=\dfrac{x+y+z}{\dfrac{3}{2}+1+\dfrac{4}{5}}=\dfrac{10}{33}\)

\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{10}{33}.\dfrac{3}{2}=\dfrac{5}{11}\\y=\dfrac{10}{33}.1=\dfrac{10}{33}\\z=\dfrac{10}{33}.\dfrac{4}{5}=\dfrac{8}{33}\end{matrix}\right.\)