Question

2x-138=2^3.2^2

3^3+2^2-(6x-12)=1

x:(12^3/4^3)=27

Answer 1

2x-138=2^5

2x-138=32

2x=32+138

2x=170

x=85

câu 2

27+4-(6x-12)=1

27+4-6x+12=1

31-6x+12=1

43-6x=1

6x-=43-1=42

x=42:6=7

câu 3

x:\(\frac{\left(3\cdot4\right)^3}{4^3}\)=27

x:\(\frac{3^3\cdot4^3}{4^3}\)=27

x:3^3=27

x:27=27

x=27*27=729

Answer 2

2x-138=2^5  

2x=138+32

2x=170

x=85

3^3+2^2-6x+12=1

-6x+13+12=1

6x=24

x=4

x:(12^3/4^3)=27

x:3^3=27

x:27=27

x=729

Answer 3

1)  2x-138=2³.2²

<=>2x-138 =8.4

<=>2x-198=32

<=>2x=230

<=>x=115

Vậy x=115

2)   3³+2²-(6x-12)=1

<=>9+4-6x+12=1

<=>-6x=1-12-4-9

<=>-6x=-24

<=>x=4

Vậy x=4

3)  x:(12³/4³)=27

<=>x:\(\frac{4^3.3^3}{4^3}\)=27

<=>x:9=27

<=>x=243

Vậy x= 243