Question

(2.x-1)^2 = 10^2 -19

Mấy bạn hay mấy anh chị giải hộ em nha

Answer 1

\(\left(2x-1\right)^2=10^2-19\)

\(\left(2x-1\right)^2=100-19\)

\(\left(2x-1\right)^2=81\)

\(\left(2x-1\right)^2=9^2\)

\(2x-1=9\)

\(2x=9+1\)

\(2x=10\)

\(x=10:2\)

\(\Rightarrow x=5\)

Answer 2

\(\left(2x-1\right)^2=10^2-19\)

\(\left(2x-1\right)^2=100-19\)

\(\left(2x-1\right)^2=81\)

mà 81 = 9² 

=> ( 2x - 1 ) ² = 9² 

=> 2x - 1 = 9 

     x = 5 

Vậy x = 5 

Answer 3

(2x-1)^2=81

Ta có \(\sqrt{81}\)=9

2x-1=9

2x=9+1=10

x=10:2=5

Answer 4

mấy chế lm thiếu hết òi , số chẵn sẽ chia ra lm 2 trường hợp 

\(\left(2.x-1\right)^2=10^2-19\)

\(\left(2x-1\right)^2=100-19\)

\(\left(2x-1\right)^2=81\)

\(\left(2x-1\right)^2=9^2\)

\(\Rightarrow\orbr{\begin{cases}2x-1=9\\2x-1=-9\end{cases}}\Rightarrow\orbr{\begin{cases}2x=10\\2x=-8\end{cases}}\Rightarrow\orbr{\begin{cases}x=5\\x=-4\end{cases}}\)

Answer 5

\(\sqrt{ỨAQW\frac{1}{4\hept{\begin{cases}ư22\\123\hept{\begin{cases}2\\1\\2\hept{\begin{cases}2\\3\hept{\begin{cases}2\\2\\3^2\end{cases}}\end{cases}}\end{cases}}\end{cases}}}DCS^{12}221_{21231}^2^{21}\overline{\supseteq}\cos^2_{21ew\delta}\tan3e}\)SSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO