Question

2⁹¹ và 5³⁵

Answer 1

\(2^{91}=2^{13\cdot7}=\left(2^{13}\right)^7=8192^7\\ 5^{35}=5^{5\cdot7}=\left(5^5\right)^7=3125^7\\ 8192>3125\Rightarrow8192^7>3125^7\Leftrightarrow2^{91}>5^{35}\)

Vậy \(2^{91}>5^{35}\)

Answer 2

\(2^{91}=\left(2^{13}\right)^7=8192^7\)

\(5^{35}=\left(5^5\right)^7=3125^7\)

\(8192^7>3125^7\)

\(\Rightarrow2^{91}>5^{35}\)