Question

\(20x^5:\left(-12x\right)\)

\(6x^3y:\left(-9x^2\right)\)

Answer 1

1, = \(\dfrac{-5x^4}{3}\)

2, = \(\dfrac{-2xy}{3}\)

Answer 2

\(20x^5\div\left(-12x\right)=\dfrac{-5}{3}x^4\)

Answer 3

\(6x^3y\div\left(-9x^2\right)=\dfrac{-2}{3}xy\)