Vì Ax // BC nên:
\(\widehat{A_1}=\widehat{C}=50^o\) (hai góc so le trong)
\(\widehat{B}+\widehat{BAx}=180^o\) (hai góc trong cùng phía)
\(\Rightarrow\widehat{BAx}=180^o-\widehat{B}=180^o-70^o=110^o\)
\(\Rightarrow\widehat{A_1}+\widehat{A_2}=110^o\)
\(\Rightarrow50^o+\widehat{A_2}=110^o\)
\(\Rightarrow\widehat{A_2}=110^o-50^o=60^o\)
Vậy \(\widehat{A_1}=50^o;\widehat{A_2}=60^o\)