1+1/3+1/5...+1/97+1/99
a= _____________________________
1/1x99+1/3x97+1/5x95...+1/49x51
a=?
A=1x99+3x97+...+49x51
Tính A
giúp mk nha gấp lắm rồi##
\(SimplifyA=\frac{1+\frac{1}{3+}+\frac{1}{5}...+\frac{1}{99}}{\frac{1}{1x99}+\frac{1}{3x97}+...+\frac{1}{49x51}}\)
Simplify:\(A=\frac{1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{99}}{\frac{1}{1x99}+\frac{1}{3x97}+...+\frac{1}{49x51}}\)
Tính tổng :
A = 1x32 +3.52 +5x72 + ... +97x992
B = 1x99 + 2x98 + 3x97 + .....+ 49x51 +50 x50
4+3/5+3/7+...+3/95+3/97+3/99
1/99+1/3*97+1/5*95+..+1/95*5+1/97*3+1/99*1
tính A= (1+1/3+1/5+...+1/95+1/97+1/99) /(1/1*99+1/3*97+1/5*95+...+1/95*5+1/97*3+1/99*1)
(5-x)+(7-x)+(9-x)+...+(95-x)+(97-x)=47×45