A=\(\frac{10^8-1+3}{10^8-1}\)=1+\(\frac{3}{10^8-1}\)
B=\(\frac{10^8-3+3}{10^8-3}\)=1+\(\frac{3}{10^8-3}\)
Vì \(\frac{3}{10^8-1}\)<\(\frac{3}{10^8^{ }-3}\)
=>A<B
A = \(\frac{10^8+2}{10^8-1}\)
A = \(\frac{100000000+2}{100000000-1}\)
A = \(\frac{100000002}{99999999}\)
A = 1,00000003
B = \(\frac{10^8}{10^8-3}\)
B = \(\frac{100000000}{100000000-3}\)
B = \(\frac{100000000}{99999997}\)
B = 1,00000003
Vì 1,00000003 = 1,00000003
nên A = B
dug thi tk nha