Question

1.l2x-1l + 3 = 3

2.lx-2l + 1 = 2

3.lx-1l+3 = 1

4.lx²-9l + lx+3l = 0

5.lx-2l = x - 2

6. lx-3l = 3-x

Cac ban giup minh giai nhanh nhan vi thu tu minh nop roi

Answer 1

\(\left|2x-1\right|+3=3\)

\(\left|2x-1\right|=3-3\)

\(\left|2x-1\right|=0\)

\(\Leftrightarrow2x-1=0\Leftrightarrow x=\frac{1}{2}\)

KL:....................

\(\left|x-2\right|+1=2\)

\(\left|x-2\right|=1\)

\(\Rightarrow\orbr{\begin{cases}x-2=1\\x-2=-1\end{cases}}\Rightarrow\orbr{\begin{cases}x=3\\x=1\end{cases}}\)

KL:........................................

Câu 3 tương tự

lát mk làm tiếp cho

Answer 2

Ta có: \(\hept{\begin{cases}\left|x^2-9\right|\ge0\forall x\\\left|x+3\right|\ge0\forall x\end{cases}}\)

Mà \(\left|x^2-9\right|+\left|x+3\right|=0\)

\(\Rightarrow\hept{\begin{cases}\left|x^2-9\right|=0\\\left|x+3\right|=0\end{cases}\Leftrightarrow\hept{\begin{cases}x^2-9=0\\x=-3\end{cases}\Leftrightarrow}\hept{\begin{cases}x^2=9\\x=-3\end{cases}\Leftrightarrow}\hept{\begin{cases}x=\pm3\\x=-3\end{cases}\Rightarrow}x=-3}\)

Vậy \(x=-3\)

\(\left|x-2\right|=x-2\)

\(\Rightarrow x-2\ge0\forall x\)

\(\Rightarrow x\ge2\)

Vậy \(x\ge2\)

\(\left|x-3\right|=3-x\)

\(\Rightarrow\left|x-3\right|=-\left(x-3\right)\)

\(\Rightarrow x-3\le0\)

\(\Rightarrow x\le3\)

Vậy \(x\le3\)

Answer 3

Gợi ý :

1) phá trị tuyệt đối bằng 2TH

2) phá trị tuyệt đối bằng bình phương trong căn bậc 2 , rồi phá căn = cách bình phương 2 vế .

Answer 4

cho hoi A ngược bạn kudo shinichi viết là j vậy

Answer 5

1/\(\left|2x-1\right|+3=3\Leftrightarrow\left|2x-1\right|=0\Leftrightarrow2x-1=0\Leftrightarrow2x=1\Leftrightarrow x=\frac{1}{2}.\)

2/\(\left|x-2\right|+1=2\Leftrightarrow\left|x-2\right|=3\)

\(\Leftrightarrow\hept{\begin{cases}x-2=3\\x-2=-3\end{cases}\Leftrightarrow\hept{\begin{cases}x=5\\x=-1\end{cases}}}\)

3/ \(\left|x-1\right|+3=1\Leftrightarrow\left|x-1\right|=-2\Leftrightarrow x\in\varnothing\)

Answer 6

a, \(\left|2x-1\right|+3=3\Leftrightarrow\left|2x-1\right|=0\Leftrightarrow2x-1=0\Leftrightarrow x=\frac{1}{2}\)

b, \(\left|x-2\right|+1=2\Leftrightarrow\left|x-2\right|=1\)

TH1 : \(x-2=1\Leftrightarrow x=3\)

TH2 : \(x-2=-1\Leftrightarrow x=1\)

c, \(\left|x-1\right|+3=1\Leftrightarrow\left|x-1\right|=-2\)vô lí 

\(\left|x-1\right|\ge0\forall x;-2< 0\)

=> PT vô nghiệm 

Answer 7

\(\left|x-2\right|=x-2\)

TH1 : \(x-2=-x+2\Leftrightarrow2x=4\Leftrightarrow x=2\)

TH2 : \(x-2=x-2\Leftrightarrow4\ne0\)

\(\left|x-3\right|=3-x\)

TH1 : \(x-3=3-x\Leftrightarrow2x-6=0\Leftrightarrow x=3\)

TH2 : \(x-3=x-3\)vô lí 

Vậy x = 3