\(14a,bc:81=a,bc\)
\(\Rightarrow14a,bc:81\cdot100=a,bc\cdot100\)
\(\Rightarrow14a,bc:81=abc\)
\(\Rightarrow14000+abc=abc\cdot81\)
\(\Rightarrow abc\cdot80=14000\)
\(\Rightarrow abc=175\)
Hay a,bc = 1,75
14a,bc:81=a,bc
⇒14a,bc:81·100=a,bc·100
⇒14a,bc:81=abc
⇒14000+abc=abc·81
⇒abc·80=14000
14a,bc:81=a,bc
=>(14a,bc:81)*100=a,bc*100
=>14abc:81=abc
=>14000+abc=abc*81
=>abc*80=14000
=>abc=14000/80=175 hay a,bc=1,75