\(\left(\dfrac{1}{3}-x\right)^2+\dfrac{3}{2}=\dfrac{1}{5}.\)
\(\left(\dfrac{1}{3}-x\right)^2=\dfrac{1}{5}-\dfrac{3}{2}.\)
\(\left(\dfrac{1}{3}-x\right)^2=\dfrac{13}{10}.\)
Tới đây \(\Rightarrow\) đề sai :vvv
a ) 4 . 3^x-1 + 2 . 3^x+2 = 4 . 3^6 + 2 . 3^9
b ) 5^x+4 - 3 . 5^x+3 = 2 . 5^11
c ) 11 . 6^x-1 = 11 . 6^11 + 2 . 6^13
A= 1-|2x-3|
B= |x-3|-|5-x|
C=4-|5x+2|-|3y+12|
D=5-3(x+1)^2
E=1/2(x+1)^2+3
F=15/4+3|x-1|
G=2021/2020+2019(x-2108)^2
Tìm x biết:
1)25/12x+11/15=9/10
2)3/2x-2/5=1/3x-1/4
3)29/12[x]-5/6=3/8
4)[4x+3/4]-5/4=2
5)2x+2x+3=144
Tìm x biết
1)1/4+1/3:1/2x=-5
2)-4/5-2/3:x=-5/12
a ) (-\(\)\(\dfrac{4}{3}\)x + \(\dfrac{1}{2}\))2 = \(\dfrac{1}{4}\)
b) 3 x + 3 x+2= 20
c) ( \(\dfrac{1}{2}\)) x+ (\(\dfrac{1}{2}\))x+2= \(\dfrac{5}{4}\)
Giúp mk với !!! Ngày mai mk làm kiểm tra rồi !!! PLEASE
(x-2/3)^3=1/27
(X+0,7)^3=-27
(2/3x-1/3)^5=1/243
tìm x biết
a)3/4+1/4:x=2/5
b)x/-2=-8/x(x khác 0)
c)(x-1)/5=20/x-1
d)(x-3/5)^2=4
Nhờ mọi người giúp mình vs!
Tìm x thuộc Q khi:
a)3x-1 =243
b)\(\left(\dfrac{2}{3}\right)^{x+1}=\dfrac{8}{4}\)
c) 3x+3x+2=270
d) \(\left(x-\dfrac{5}{2}\right)^2=144\)
e) \(\left(2x+1\right)^3=\dfrac{215}{27}\)
f) (2x-1)5 = -243
h) (27-1)2 = (2x-1)2
i) (2x+1)2 + (x+1)10 = 0
k) \(\dfrac{x-2}{5}=\dfrac{X+3}{2}\)
l) \(\dfrac{2}{x}=\dfrac{x}{50}\)
m) \(\dfrac{\left(x-3\right)}{4}=\dfrac{4}{x+3}\)
n) \(|x+\dfrac{3}{5}|-|x-\dfrac{7}{3}|\)
Bài 1: Tìm x, biết
\(a,\frac{2}{3}-\frac{1}{3}.\left(x-\frac{3}{2}\right)-\frac{1}{2}.\left(2x+1\right)=5\)
\(b,\left(x+\frac{1}{2}\right).\left(x-\frac{3}{4}\right)=0\)
\(c,\left(2x-5\right)^4=81\)
\(d,3^{x+1}+3^{x+3}=810\)
