1+2+3+4+...+x=1275
[(x-1):1+1].(1+x):2=1275
x.(x+1)=1275.2
x.(x+1)=2550
x.(x+1)=50.51
x.(x+1)=50.(50+1)
=> x=50
chúc bạn học tốt nha
ủng hộ mk với nha
\(1+2+3+4+...+x=1275\)
\(\Rightarrow\frac{\left[\left(x-1\right):1+1\right].\left(x+1\right)}{2}=1275\)
\(\Rightarrow\frac{x\left(x+1\right)}{2}=1275\)
\(\Rightarrow x\left(x+1\right)=1275\times2=2550=50\times51\)
Vậy x = 50
\(1+2+3+4+.......+x=1275\)
<=>\(\left(x+1\right).\text{[}\left(x-1\right):1+1\text{]}\)
<=> \(=1275\)
\(2\)
<=>\(\left(x+1\right).\text{[}\left(x-1\right)+1\text{]}=2550\)
<=> \(\left(x+1\right).x=2550\text{ }\)
<=>\(\left(x+1\right).x=51.50\)
<=> \(x=50\)vậy \(x=50\)
x= 50 nhé=))))))))))))