a/ 1/2x9 + 1/9x7+1/7x19+...........+1/252x509
b/1/10x9+1/18x13+1/26x17+..................+1/802x405
Ai BIẾT CÂU NÀY GIÚP MIK VỚI
a) C=1/9x10+1/18x13+1/26x17+.......+1/802x405
b)D=2/4x7-3/5x9+2/7x10-3/9x13+......+2/302x304+3/401x405
Q=\(\frac{1}{2x9}\)+\(\frac{1}{9x7}\)+\(\frac{1}{7x19}\)+.......+\(\frac{1}{252x509}\)
R=\(\frac{1}{10x9}\)+\(\frac{1}{18x13}\)+\(\frac{1}{26x17}\)+.....+\(\frac{1}{802x405}\)
S=\(\frac{2}{4x7}\)\(-\)\(\frac{3}{5x9}\)+\(\frac{2}{7x10}\)\(-\)\(\frac{3}{9x13}\)+.........+\(\frac{2}{301x304}\)+\(\frac{3}{401x403}\)
TÍNH TỔNG S=1/5x6+1/10x9+1/15x12+.....+1/3350x2013
TÍNH TỔNG S=1/5x6+1/10x9+1/15x12+.....+1/3350x2013
10x9+9x10
20x30+2^3
a)12^3x3^3 ; b)2x8^4 ; c)(8^11x3^17):(27^10x9^15)
giải giúp mk với
hãy điền dấu +,- thích hợp
1...1...1...1...1...1...1...1...1...1=10
1...1...1...1...1...1...1...1...1...1=9
1...1...1...1...1...1...1...1...1...1=8
1...1...1...1...1...1...1...1...1...1=7
1...1...1...1...1...1...1...1...1...1=6
1...1...1...1...1...1...1...1...1...1=5
1...1...1...1...1...1...1...1...1...1=4
1...1...1...1...1...1...1...1...1...1=3
1...1...1...1...1...1...1...1...1...1=2
1...1...1...1...1...1...1...1...1...1=1
1...1...1...1...1...1...1...1...1...1=0