\(1.x+\frac34=\frac{1}{36}\)
\(x=\frac{1}{36}-\frac34=\frac{1}{36}-\frac{27}{36}\)
\(x=-\frac{26}{36}=-\frac{13}{18}\)
\(2.x+\frac13=\frac25-\left(-\frac14\right)\)
\(x+\frac13=\frac{13}{20}\)
\(x=\frac{13}{20}-\frac13=\frac{19}{60}\)
\(3.\frac35x-\frac12=\frac27\frac{3}{}\)
\(5x=\frac27+\frac12\)
\(\frac35x=\frac{11}{14}\)
\(x=\frac{11}{14}:\frac35=\frac{11}{14}\cdot\frac53\)
\(x=\frac{55}{42}\)
\(4.\frac14+\frac13:2x=-5\)
\(\frac{1}{6x}=-5-\frac14\)
\(\frac{1}{6x}=-\frac{21}{4}\)
4 = -126x
x = \(\frac{4}{-126}=-\frac{2}{63}\)
5. bạn viết latex để đề rõ hơn nha bạn
\(6.\left(x-\frac23\right)^3=\frac{1}{27}\)
\(\left(x-\frac23\right)^3=\left(\frac13\right)^3\)
\(\Rightarrow x-\frac23=\frac13\)
\(x=\frac13+\frac23=1\)
\(7.\frac{14}{9}-\left(2x+5\right)=3^2\cdot\frac{5}{27}\)
\(\frac{14}{9}-\left(2x+5\right)=\frac53\)
\(2x+5=\frac{14}{9}-\frac53\)
\(2x+5=-\frac19\)
\(2x=-\frac19-5\)
\(2x=-\frac{46}{9}\)
\(x=-\frac{46}{9}:2=-\frac{23}{9}\)
\(8.\frac{x^3}{\left(-\frac12\right)^2}=\frac12\)
\(\frac{x^3}{\frac14}=\frac12\)
\(\Rightarrow4x^3=\frac12\)
\(\Rightarrow x^3=\frac18\)
\(x^3=\left(\frac12\right)^3\Rightarrow x=\frac12\)
\(9.\left(\frac34x-2,5\right)^3=-8\)
\(\left(\frac34x-2,5\right)^3=\left(-2\right)^3\)
\(\frac34x-2,5=-2\)
\(\frac34x=-2+2,5\)
\(\frac34x=\frac12\)
\(x=\frac12:\frac34=\frac23\)
\(10.\left(x-\frac14\right)^2=\frac{1}{36}\)
\(\) \(\left[\begin{array}{l}x-\frac14=\frac16\Rightarrow x=\frac{5}{12}\\ x-\frac14=-\frac16\Rightarrow x=\frac{1}{12}\end{array}\right.\)
\(x\in\left\lbrace\frac{5}{12};\frac{1}{12}\right\rbrace\)
