Lời giải:
$|1-\sqrt{23}|+23-\sqrt{23}-|-2023|^0=\sqrt{23}-1+23-\sqrt{23}-1$
$=23-2=21$
Lời giải:
$|1-\sqrt{23}|+23-\sqrt{23}-|-2023|^0=\sqrt{23}-1+23-\sqrt{23}-1$
$=23-2=21$
a) cho C = 3 - \(3^2+3^3-3^4+3^5-3^6+...+3^{23}-3^{24}\), chứng minh rằng C \(⋮\) 420
b) tìm x và y biết \(\left(x+1\right)^{2022}+\left(\sqrt{y-1}\right)^{2023}=0\)
a,1/7 * 3/8 + 1/7 * 5/8 + ((- 1) ^ 2023)/7
b,- 3 - 16/23 - sqrt(4/49) - 7/23 + ((- 3) ^ 2)/7
c,(4 ^ 2 * 0.2 ^ 3)/(2 ^ 6)
Giúp mik vớiiii, mik cảm ơn
a) \(4.\left(-\dfrac{1}{2}\right)^3\)\(-2.\left(-\dfrac{1}{2}\right)^2\)+\(3.\left(-\dfrac{1}{2}\right)\)+1
b) \(8.\sqrt{9}\)\(-\sqrt{64}\)
c) \(\sqrt{\dfrac{9}{16}}\)\(+\dfrac{25}{46}\)\(:\dfrac{5}{23}\)\(-\dfrac{7}{4}\)
đung cho 5 sao
a) \(\sqrt{\left(-7\right)^2}+\sqrt{\dfrac{25}{16}}-\dfrac{3}{2}\) b) \(23\dfrac{1}{3}.\dfrac{-1}{4}-13\dfrac{1}{3}.\dfrac{-1}{4}\)
tính \(2^{3+\frac{1}{4}}\cdot16+\sqrt{25}-\left|23\right|\)
1. So sánh
\(\sqrt{23}+\sqrt{15}\) và \(\sqrt{83}\)
2. Tính giá trị của biểu thức
M = \(\left(x-4\right)^{\left(x-5\right)^{\left(x-6\right)^{\left(x+6\right)^{\left(x+5\right)}}}}\)
23+23+23+23=
\(\sqrt{4}\)+\(\sqrt{25}\)
CMR: \(2,\left(3\right)<\frac{17-2\sqrt{23}}{3}<3\)
giúp t nhé
\(\left(1\dfrac{4}{23}-\dfrac{5}{21}\right)-\left(\dfrac{4}{23}-\dfrac{3}{4}\right)-\dfrac{16}{21}\)