a) 17x3/30x3 và 51 /92
=51/90 > 51/92
b) -3x3 /5x3 và -9/23
-9/15> -9/23
c)-15x10101/23x10101 và -151515/232323
=-151515/232323=-151515/232323
\(\text{a) }\dfrac{17}{30}\text{ và }\dfrac{51}{92}\\ \text{Ta có : }\dfrac{17}{30}=\dfrac{17\cdot3}{30\cdot3}=\dfrac{51}{90}\\ \text{Mà }\dfrac{51}{90}>\dfrac{51}{92}\\ \Rightarrow\dfrac{17}{30}>\dfrac{51}{92}\\ \text{Vậy }\dfrac{17}{30}>\dfrac{51}{92}\\ \\ \)
\(\text{b) }-\dfrac{3}{5}\text{ và }-\dfrac{9}{23}\\ \text{Ta có : }-\dfrac{3}{5}=-\dfrac{3\cdot3}{5\cdot3}=-\dfrac{9}{15}\\ \text{ Mà }-\dfrac{9}{15}< -\dfrac{9}{23}\\ \Rightarrow-\dfrac{3}{5}< -\dfrac{9}{23}\\ \text{Vậy }-\dfrac{3}{5}< -\dfrac{9}{23}\\ \\ \)
\(\text{c) }-\dfrac{15}{23}\text{ và }\dfrac{-151515}{232323}\\ \text{Ta có : }-\dfrac{151515}{232323}=-\dfrac{15\cdot10101}{23\cdot10101}=\dfrac{-15}{23}\\ \text{Vậy }-\dfrac{15}{23}=\dfrac{-151515}{232323}\)