Question

3) Giải phương trình \( 2\sqrt{x^2 - 4x + 4} - 10 = 0 \)

Answer 1

\(2\sqrt{x^2-4x+4}-10=0\)

=>\(2\cdot\sqrt{\left(x-2\right)^2}-10=0\)

=>\(2\left|x-2\right|=10\)

=>|x-2|=5

=>\(\left[{}\begin{matrix}x-2=5\\x-2=-5\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=7\\x=-3\end{matrix}\right.\)

Answer 2

=>2\(\sqrt{\left(x-2\right)^2}\)-10=0

=>2(x-2)-10=0

=>2x-4-1-=0

=>2x-5=0

=>x=5/2