Xét tứ giác ABCD có \(\widehat{A}+\widehat{B}+\widehat{BCD}+\widehat{CDA}=360^0\)
=>\(\widehat{BCD}+\widehat{CDA}=360^0-100^0-90^0=170^0\)
=>\(\widehat{ODC}+\widehat{OCD}=\dfrac{170^0}{2}=85^0\)
Xét ΔOCD có \(\widehat{OCD}+\widehat{ODC}+\widehat{DOC}=180^0\)
=>\(\widehat{DOC}=180^0-85^0=95^0\)