1A: Vì \(0.2\cdot\dfrac{-2}{9}=\dfrac{1}{60}\cdot\dfrac{-8}{3}\)
nên \(\dfrac{0.2}{\dfrac{1}{60}}=\dfrac{-\dfrac{8}{3}}{-\dfrac{2}{9}};\dfrac{0.2}{-\dfrac{8}{3}}=\dfrac{\dfrac{1}{60}}{-\dfrac{2}{9}};\dfrac{\dfrac{1}{60}}{0.2}=\dfrac{-\dfrac{2}{9}}{-\dfrac{8}{3}};\dfrac{-\dfrac{8}{3}}{0,2}=\dfrac{-\dfrac{2}{9}}{\dfrac{1}{60}}\)
1B:
\(\dfrac{0.25}{1.5}=\dfrac{\dfrac{25}{18}}{\dfrac{25}{3}}\); \(\dfrac{1.5}{0.25}=\dfrac{\dfrac{25}{3}}{\dfrac{25}{18}}\)
\(\dfrac{0.25}{\dfrac{25}{18}}=\dfrac{1.5}{\dfrac{25}{3}}\); \(\dfrac{\dfrac{25}{18}}{0,25}=\dfrac{\dfrac{25}{3}}{1,5}\)
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