a: \(x+\dfrac{1}{4}=\dfrac{4}{3}\)
=>\(x=\dfrac{4}{3}-\dfrac{1}{4}=\dfrac{16-3}{12}=\dfrac{13}{12}\)
b: \(-x-\dfrac{2}{3}=-\dfrac{6}{7}\)
=>\(x+\dfrac{2}{3}=\dfrac{6}{7}\)
=>\(x=\dfrac{6}{7}-\dfrac{2}{3}=\dfrac{18-14}{21}=\dfrac{4}{21}\)
c: \(x^2=16\)
=>\(x^2=4^2\)
=>\(\left[{}\begin{matrix}x=4\\x=-4\end{matrix}\right.\)
d: \(x:\left(-2\dfrac{1}{15}\right)+3\dfrac{1}{2}=-\dfrac{3}{4}\)
=>\(x:\dfrac{-31}{15}=-\dfrac{3}{4}-\dfrac{7}{2}=\dfrac{-3-14}{4}=\dfrac{-17}{4}\)
=>\(x=\dfrac{-17}{4}\cdot\dfrac{-31}{15}=\dfrac{527}{60}\)
e: \(x-\dfrac{1}{3}=2-3x\)
=>\(x+3x=2+\dfrac{1}{3}\)
=>\(4x=\dfrac{7}{3}\)
=>\(x=\dfrac{7}{3}:4=\dfrac{7}{12}\)
f: \(\left(3\dfrac{5}{7}x-1\dfrac{5}{7}x\right)-\dfrac{1}{3}=\dfrac{2}{3}\)
=>\(x\left(3+\dfrac{5}{7}-1-\dfrac{5}{7}\right)=\dfrac{2}{3}+\dfrac{1}{3}\)
=>2x=1
=>\(x=\dfrac{1}{2}\)
