Bài 8: Phân tích đa thức thành nhân tử bằng phương pháp nhóm các hạng tử

Bạn chưa đăng nhập. Vui lòng đăng nhập để hỏi bài

\(13,x^2-x-3x+3\\ =x\left(x-1\right)-3\left(x-1\right)\\ =\left(x-3\right)\left(x-1\right)\\ ---\\ 16,x^3-3x^2-4x+12\\ =x^2\left(x-3\right)-4\left(x-3\right)\\ =\left(x-3\right)\left(x^2-4\right)\\ =\left(x-3\right)\left(x-2\right)\left(x+2\right)\\ ---\\ 15,x^2-2x-3x+6\\ =x\left(x-2\right)-3\left(x-2\right)\\ =\left(x-3\right)\left(x-2\right)\\ ---\\ 14,x^2+x+3x+3\\ =x\left(x+1\right)+3\left(x+1\right)\\ =\left(x+3\right)\left(x+1\right)\\ ---\\ 17,45+x^3-5x^2-9x\\ =x^2\left(x-5\right)-9\left(x-5\right)\\ =\left(x^2-9\right)\left(x-5\right)\\ =\left(x-3\right)\left(x+3\right)\left(x-5\right)\\ ---\\ 18,x^5+x^4+x+1\\ =x^4\left(x+1\right)+\left(x+1\right)\\ =\left(x^4+1\right)\left(x+1\right)\)

\(26,3x^2-3xy-5x+5y\\ =3x\left(x-y\right)+5\left(x-y\right)\\ =\left(3x+5\right)\left(x-y\right)\\ ---\\ 27,xz+yz-5x-5y\\ =z\left(x+y\right)-5\left(x+y\right)\\ =\left(z-5\right)\left(x+y\right)\\ ----\\ 21,x^5+x^4+x+1\\ =x^4\left(x+1\right)+\left(x+1\right)\\ =\left(x^4+1\right)\left(x+1\right)\\ ---\\ 24,ax+ay+bx+by\\ =a\left(x+y\right)+b\left(x+y\right)\\ =\left(a+b\right)\left(x+y\right)\\ ---\\ 27,5a^2-5ax-7a+7x\\ =5a\left(a-x\right)-7\left(a-x\right)\\ =\left(5a-7\right)\left(a-x\right)\\ ---\\ 30,3x^2-3xy-5x+5y\\ =3x\left(x-y\right)-5\left(x-y\right)\\ =\left(3x-5\right)\left(x-y\right)\)

\(19,x^4-9x^3+x^2-9x\\ =x^3\left(x-9\right)+x\left(x-9\right)\\ =\left(x^3+x\right)\left(x-9\right)\\ =x\left(x^2+1\right)\left(x-9\right)\\ ---\\ 22,x^3+x^2+x+1\\ =x^2\left(x+1\right)+\left(x+1\right)\\ =\left(x^2+1\right)\left(x+1\right)\\ ---\\ 25,x^2-xy+x-y\\ =x\left(x-y\right)+\left(x-y\right)\\ =\left(x-y\right)\left(x+1\right)\\ ---\\ 20,x^3+x^2+x+1\\ =x^2\left(x+1\right)+\left(x+1\right)\\ =\left(x+1\right)\left(x^2+1\right)\\ ---\\ 28,x^2-xy+x-y\\ =x\left(x-y\right)+\left(x-y\right)\\ =\left(x+1\right)\left(x-y\right)\\ ---\\ 23,x^3+7x^2-4x-28\\ =x^2\left(x+7\right)-4\left(x+7\right)\\ =\left(x^2-4\right)\left(x+7\right)\\ =\left(x-2\right)\left(x+2\right)\left(x+7\right)\)

Nguyễn Lê Phước Thịnh
3 tháng 12 2023 lúc 10:57

24: ax+ay+bx+by

=(ax+ay)+(bx+by)

=a(x+y)+b(x+y)

=(x+y)(a+b)

25: \(x^2-xy+x-y\)

\(=\left(x^2-xy\right)+\left(x-y\right)\)

\(=x\left(x-y\right)+\left(x-y\right)\)

\(=\left(x-y\right)\left(x+1\right)\)

26: \(3x^2-3xy-5x+5y\)

\(=\left(3x^2-3xy\right)-\left(5x-5y\right)\)

\(=3x\left(x-y\right)-5\left(x-y\right)\)

\(=\left(x-y\right)\left(3x-5\right)\)

27: \(5a^2-5ax-7a+7x\)

\(=\left(5a^2-5ax\right)-\left(7a-7x\right)\)

\(=5a\left(a-x\right)-7\left(a-x\right)\)

\(=\left(a-x\right)\left(5a-7\right)\)

28: \(x^2-xy+x-y\)

\(=\left(x^2-xy\right)+\left(x-y\right)\)

\(=x\left(x-y\right)+\left(x-y\right)\)

\(=\left(x-y\right)\left(x+1\right)\)

29: \(xz+yz-5x-5y\)

\(=\left(xz+yz\right)-\left(5x+5y\right)\)

\(=z\left(x+y\right)-5\left(x+y\right)\)

\(=\left(x+y\right)\left(z-5\right)\)

30: \(3x^2-3xy-5x+5y\)

\(=\left(3x^2-3xy\right)-\left(5x-5y\right)\)

\(=3x\left(x-y\right)-5\left(x-y\right)\)

\(=\left(x-y\right)\left(3x-5\right)\)


Các câu hỏi tương tự
Tạ Thu Hương
Xem chi tiết
Nguyễn Lâm Tùng
Xem chi tiết
Hiền Trâm
Xem chi tiết
Nguyễn Thị Ngọc Lan
Xem chi tiết
Đoàn Phan Hưng
Xem chi tiết
Hiếu
Xem chi tiết
Vịt nho  :U
Xem chi tiết
Đoàn Phan Hưng
Xem chi tiết