a: \(A=\dfrac{1.3-2.6}{2.6}-\dfrac{5}{6}:2=\dfrac{-1}{2}-\dfrac{5}{12}=-\dfrac{11}{12}\)
\(B=\left(5+\dfrac{7}{8}-2-\dfrac{1}{4}-\dfrac{1}{2}\right):\dfrac{75}{26}=\left(3+\dfrac{1}{8}\right):\dfrac{75}{26}\)
\(=\dfrac{25}{8}\cdot\dfrac{26}{75}=\dfrac{1}{3}\cdot\dfrac{13}{4}=\dfrac{13}{12}\)
b: A<x<B
=>-11/12<x<13/12
=>\(x\in\left\{0;1\right\}\)
a) \(A=\dfrac{1,11+0,19-1,3\cdot2}{2,06+0,54}-\left(\dfrac{1}{2}+\dfrac{1}{3}\right):2\)
\(A=\dfrac{\left(1,11+0,19\right)-2,6}{2,6}-\left(\dfrac{3}{6}+\dfrac{2}{6}\right):2\)
\(A=\dfrac{1,3-2,6}{2,6}-\dfrac{5}{6}:2\)
\(A=\dfrac{-1,3}{2,6}-\dfrac{5}{6}:2\)
\(A=\dfrac{-1}{2}-\dfrac{5}{12}\)
\(A=\dfrac{-6}{12}-\dfrac{5}{12}\)
\(A=-\dfrac{11}{12}\)
\(B=\left(5\dfrac{7}{8}-2\dfrac{1}{4}-0,5\right):2\dfrac{23}{26}\)
\(B=\left(5+\dfrac{7}{8}-2-\dfrac{1}{4}-\dfrac{1}{2}\right):\dfrac{23+26+26}{26}\)
\(B=\left(3+\dfrac{7}{8}-\dfrac{2}{8}-\dfrac{4}{8}\right):\dfrac{75}{26}\)
\(B=\left(3+\dfrac{1}{8}\right)\cdot\dfrac{26}{75}\)
\(B=\left(\dfrac{24}{8}+\dfrac{1}{8}\right)\cdot\dfrac{26}{75}\)
\(B=\dfrac{25}{8}\cdot\dfrac{26}{75}\)
\(B=\dfrac{26}{24}\)
\(B=\dfrac{13}{12}\)
b) Ta có:
\(A< x< B\)
\(\Rightarrow-\dfrac{11}{12}< x< \dfrac{13}{12}\)
\(\Rightarrow x\in\left\{0;1\right\}\)
